for loop n*n matrix with a given formula
8 views (last 30 days)
Show older comments
I want to write a code for the following problem:


The code must be able to determine the head (h) at every x and y. I have constructed the formula, and now I want to construct a n*n matrix for every head at every position with a for loop. I have constructed the following:
%%Example 7.1
A=(-4/500);
B=(-2/300);
C=120;
x=-100:10:600;
y=-600:10:100;
h=zeros(71);
for i=1:71
h(i,:)=A*x(i)+B*y(71)+C;
h(:,i)=A*x(1)+B*y(72-i)+C;
end
Thanks in advance.
2 Comments
Answers (1)
YT
on 5 Mar 2018
I assume your looking for something like this, so you'll end up with a matrix h with size 71x71 (rows = x, columns = y)
clear all;
close all;
A = (-4/500);
B = (-2/300);
C = 120;
x = -100:10:600;
y = -600:10:100;
n = size(x,2);
h = zeros(n);
for i = 1:n
for j = 1:n
h(i,j) = A*x(i) + B*y(j) + C;
end
end
0 Comments
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!