How do I make a script that outputs all numbers containing a certain set of digits?

Say I want to make a vector containing all numbers with the digits [2,4,5,7,9], so 25497, 95742, etc. How can I make a script that puts all numbers in this vector?

I've tried the following:

 %
vec = zeros (1,factorial(5));
i = 0
while  i   < factorial(5)
  num           = 0;
  ii = 0;
  iii       = [2,4,5,7,9];
  while ii   < 5;                % This while loop creates a number
    randnum      = randi(5);
    eval      = iii(randnum);
    if eval > 0
      num       = num + eval*10^(ii);
      iii(randnum) = 0;
      ii = ii + 1;
    end
  end
  if not(ismember(num,vec(:)))   %This if-statement checks if the number had already been created earlier
    i = i + 1;
    vec(i) = num;                %If not, it is added to the vector
  end
end

but it is impressively inelegant and simply takes too long for larger amounts of numbers.

Answer 1

[Kai Domhardt]

digits = [2,4,5,7,9];
sum(perms(digits).*10.^[size(digits,2)-1:-1:0],2);

---

perms(digits)

creates all permutations of digits

10.^[size(digits,2)-1:-1:0]

creates a vector with the relevant orders of magnitude:

ans =
     10000        1000         100          10           1

which you can use to give your digits the right positional value:

perms(digits).*10.^[size(digits,2)-1:-1:0]

Now you only need to sum it up row wise:

sum( perms(digits).*10.^[size(digits,2)-1:-1:0] ,2)