The script run just fine when it is beside the previous created function LCinput_Callback, the problem is that i cant create a function that does the same thing, and i dont know why.
Not enough Input Arguments
3 views (last 30 days)
Show older comments
Victor Dalosto
on 15 Jan 2018
Commented: Victor Dalosto
on 15 Jan 2018
Im having problem with a script. Im trying to create a function that handles differents inputs in a GUI, convert those value, and display the result. The problem is that the script is not running the get(handles lines when its under the created function and is display the following error:
Not enough input arguments.
Error in EngineerTool1>ETConverterLenght (line 72)
LC_value1 = str2num(get(handles.LCinput,'String'));
Error in EngineerTool1>LCinput_Callback (line 134)
ETConverterLenght;
Error in gui_mainfcn (line 95)
feval(varargin{:});
Error in EngineerTool1 (line 16)
gui_mainfcn(gui_State, varargin{:});
Here is the code
function LCinput_Callback(hObject, eventdata, handles)
ETConverterLenght;
function ETConverterLenght(handles)
LC_value1 = str2num(get(handles.LCinput,'String'));
Accepted Answer
Walter Roberson
on 15 Jan 2018
Change your line
ETConverterLenght;
to
ETConverterLenght(handles);
Note: you have used "Lenght", but most people would use "Length"
More Answers (1)
Matt J
on 15 Jan 2018
Edited: Matt J
on 15 Jan 2018
The function ETConverterLenght isn't being passed an argument in the code for this callback:
function LCinput_Callback(hObject, eventdata, handles)
ETConverterLenght;
Maybe you meant to have,
function LCinput_Callback(hObject, eventdata, handles)
ETConverterLenght(handles);
0 Comments
See Also
Categories
Find more on Entering Commands in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!