compare between two results with percentage Error

Hi

can you help me with this problem , i have two results (original and calculation) , i would like to compare the original with calculation results and have the percentage error in calculation part when compare with original . for example if i have

Original =[1;2;3;1;2;3]; calculation=[1;2;3;1;2;3];

the calculation is exact the original so the percentage Error in calculation is 0% if i have

Original =[1;2;3;1;2;3]; calculation=[1;1;3;2;2;1];

the calculation is not exact the original so the percentage Error in calculation has to be 50%

thank you

Answer 1

[Alizée Perrin]

Your question is similar to this one.

Try this code :

PDif = 100*(calculation-original)./original;

[mohammed hussein]

thank you for your answer . i want to compare not by number but by similarity in numbers . if it is similar OK if it is not so it is wrong . the percentage is based on similarity in number .