how can i obtain this ?

i would like to use the command reshape to convert a vector v=11:99 to a matrix (9x9), how can i do this, can anyone help me ?

 Accepted Answer

Birdman
Birdman on 21 Nov 2017
You can not do it when v=11:99.
If you want to convert to 9x9 matrix, then you need to have 81 elements in your vector, with this you have 89. If you define it as v=11:91, then the following command will do what you want.
v=reshape(v,9,9)

13 Comments

thank you Mr,cvklpstunc, for your answer.
Birdman
Birdman on 21 Nov 2017
You are welcome, if it is helpful, you can accept the answer.
have you another way to create this matrix please ?
Birdman
Birdman on 21 Nov 2017
As I said before, 89 is a prime number and the only way to reshape it is either 89x1 or 1x89 vector. There is no other way.
i want a way without using the loop for .
Birdman
Birdman on 21 Nov 2017
Okay, you do not need for loop anyway, but you have 89 elements, either change it or you can not do anything with it.
diadalina
diadalina on 21 Nov 2017
Edited: diadalina on 21 Nov 2017
i can do it like this, A=[11:19;21:29;31:39;41:49;51:59;61:69;71:79;81:89;91:99], but i want a way more easier than this.
Birdman
Birdman on 21 Nov 2017
But you skip 20,30,40,...,90 in this case
no, that is the result , that i want, i have this way also: l=11:19; A=[l;l+10;l+20;l+30;l+40;l+50;l+60;l+70;l+80]; but i think , there is another way more easier than this.
Birdman
Birdman on 21 Nov 2017
But v=11:99 includes 20,30,40,...,90 so you need to know what you ask.
tha is the result, that i had wanted. A =
11 12 13 14 15 16 17 18 19
21 22 23 24 25 26 27 28 29
31 32 33 34 35 36 37 38 39
41 42 43 44 45 46 47 48 49
51 52 53 54 55 56 57 58 59
61 62 63 64 65 66 67 68 69
71 72 73 74 75 76 77 78 79
81 82 83 84 85 86 87 88 89
91 92 93 94 95 96 97 98 99
v=11:99;
IND=find(mod(v,10)==0);
v(IND)=[];
v=reshape(v,9,9)
that's exactly , what i want, thank you very much.

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More Answers (1)

KL
KL on 21 Nov 2017
Simpler with just one line,
bsxfun(@plus,1:9,(10:10:90).')

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