replace all the array with NaN if any of the value is NaN

i am working with some data and the condition i want to set is that, if in the data there is NaN value in any column i want to replace that whole column with NaN values. following is a screen shot of my data structure. where i am working on the third dimension (144) of the data. Thanks in advance for help

Answer 1

[KSSV]

% Generate random matrix 
  N = 10 ;
  A = rand(10) ;
  % introduce nans
  idx = randsample(1:N*N,20) ;
  A(idx) = NaN ;
  %%Repalce columns with NaN's if any NaN'present
  B = A ;
  for i = 1:N
      if any(isnan(A(:,i)))
          B(:,i) = NaN ;
      end

    end

Answer 2

[Jan]

Without a loop and bsxfun:

A    = randi(9, 4, 3, 2);
A(6) = NaN;
A(:, any(isnan(A), 1)) = NaN;

[Stephen23]

+1 I should never answer before coffee.