How to get rid of repeating values inside an array

I have a matrix

      a=[1 2 3 3 4 4 5];

I want to get rid of values 3 and 4 as they are repeating so that the output becomes

      b=[1 2 5]

Answer 1

[José-Luis]

 b = a(sum(bsxfun(@eq,a,a'))==1)

[Rokki]

Thank you very much

[José-Luis]

My pleasure.

Please keep in mind that this is inefficient for large arrays though. Just using unique() should take you where you need to go.

Answer 2

[Andrei Bobrov]

v = unique(a);
b = v(histcounts(a,[v(:);v(end)+eps]) == 1);

or

v = unique(a);
b = v(histc(a,v) == 1);

or

aa = sort(a);
t = diff(aa);
b = aa([1 t] & [t 1]);

[Rokki]

Thank you for help. I am getting an error

Undefined function 'histcounts' for input arguments of type 'double'.

[José-Luis]

histcounts() was introduced with R2014b. You don't need it though. unique() is enough. Andrei was giving you two alternatives.

[Andrei Bobrov]

fixed