how to not exceed limits of the matrix column

for eg, i have matrix A=[4 6 3 8 9 5;1 7 2 4 3 4;7 8 5 6 1 2; 1 8 4 7 10 6;] and i use a for loop to go across the column, for i =1:col .... how do i stop it before getting error of matrix exceeds dimensions

Answer 1

[José-Luis]

 your_array = rand(10,16)
 %looping through all columns
 for ii=your_array
     %ii now contains all values in column
 end

[minion001]

in a for loop, i pick call a function, which picks the most smallest elevation change, but when it goes to the edge of the column it says matrix exceeds dimension, this is my code

function[Rows,Cols]=Elevation(c,A)

[row,col]=size(A);

m=currentposition(1);

n=currentposition(2);

currentposition=[m,n]

i=1;

for i=1:col

[pick]=NewElement(currentposition, A); %this is a function im calling

Rows(i)=currentposition(1);

Cols(i)=currentposition(2);

currentposition=pick;

i=i+1;

end end

from this is get columns 1-5 but once it is on column 6 it gives me matrix exceeds dimension

[José-Luis]

Why do you do i=i+1?

It is unnecessary, if what you want is to increment the iterator index.

Why do you call both loop iterators i?

Call the first one ii and the second one jj or whatever, but definitely not the same name.

[minion001]

i did that but how do i stop getting error when im at column 6 and its searching for elements next to it, where there isn't any elements present, resulting in matrix exceeds dimensions

[José-Luis]

Columns 1-5 of what? You are not indexing into A and that is the array whose columns you are looping on.

Please use the debugger. Place a breakpoint in the line that's giving you grief and look at the arrays you are indexing into.