my question is if a=[1 2;3 4],b=[5 6;7 8],c=[9 10;11 12] the resultant matrix should be d=[1 5 9;2 6 10;3 7 11;4 8 12] this should be done using for loop?

my question is if a=[1 2;3 4],b=[5 6;7 8],c=[9 10;11 12]

the resultant matrix should be d=[1 5 9;2 6 10;3 7 11;4 8 12] this should be done using for loop?

[Maiolica]

It should be d = [15 18;21 24] because a,b and c all are of 2*2 order.

[DGM]

Nobody suggested that the goal was to take the sum. The given result for d is clearly done by reshaping the contents of a, b, and c as is shown in the other comments.

a = [1 2;3 4];
b = [5 6;7 8];
c = [9 10;11 12];
d = reshape([a; b; c].',[],3)

d = 4×3

1 5 9 2 6 10 3 7 11 4 8 12

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Answer 1

[Torsten]

Maybe

d = [a(:) b(:) c(:)]

?

Best wishes

Torsten.

[Andrei Bobrov]

>> [a(:) b(:) c(:)]
ans =
     1     5     9
     3     7    11
     2     6    10
     4     8    12

Should be:

>> d = reshape([a;b;c]',numel(a),[])
d =
     1     5     9
     2     6    10
     3     7    11
     4     8    12
>>

[sravankumar v]

thank you

[Torsten]

Then

d=[a.'(:) b.'(:) c.'(:)]

?

Best wishes

Torsten.

[Andrei Bobrov]

?

this is MATLAB and not Julia

[Torsten]

Writing the transposed matrix as column vector does not work this way ?

Any recommendation ?

Best wishes

Torsten.

[Torsten]

Don't know "Julia", but a combination of both features (.' and (:)) in one command line is quite intuitive.

Less cumbersome than

a=a.';
b=b.';
c=c.'; 
d=[a(:) b(:) c(:)];

Best wishes

Torsten.