i want to take different values in each loop ?

close all;
clear all;
clc;

v=[1 2 3;4 5 6;7 8 9]
[n m]=size(v);
w=double(abs(rand(n,5)));
h=double(abs(rand(5,m)));
% L2=norm(w,2);
l2=zeros(3,1)
%l2 norm column wise
for i=1:5
l2(i)=norm(w(:,i),2)
end

%l1 norm column wise
l1=zeros(5,1);
for k=1:5
    l1(k)=(l2(k)*(sqrt(3)-(sqrt(3)-1)*0.9))

end 
%%i want to make a loop such that it takes value of l1 for each w 
%%that is I want to avoid rewriting the below code for taking each value of l1.
for i1=1:3

      w(i1)=w(i1)+(l1(1)-sum(w(:,i1)))/3
  end

for i2=1:3

      w(i2)=w(i2)+(l1(2)-sum(w(:,i2)))/3
  end
  for i3=1:3

      w(i3)=w(i3)+(l1(3)-sum(w(:,i3)))/3

end
for i4=1:3

      w(i4)=w(i4)+(l1(4)-sum(w(:,i4)))/3
  end
  for i5=1:3

      w(i5)=w(i5)+(l1(5)-sum(w(:,i5)))/3
  end

[Stephen23]

@ kitty varghese: why are you using loops anyway? These are simple arithmetic operations, which could easily be vectorized:

https://www.mathworks.com/help/matlab/matlab_prog/vectorization.html

Answer 1

[kitty varghese]

u can make an outer loop for changing the value of l1

for i0=1:5
    for i1=1:3
        w(i1)=w(i1)+(l1(i0)-sum(w(:,i1)))/3
    end
end

[Jan]

This looks strange:

w(i1)=w(i1)+(l1(1)-sum(w(:,i1)))/3

you access w as a vector on the left, and as a matrix on the right.

w=double(abs(rand(n,5)));

is the same as

w = rand(n,5);

Instead of

l1=zeros(5,1);
for k=1:5
  l1(k)=(l2(k)*(sqrt(3)-(sqrt(3)-1)*0.9))
end

you can write:

l1 = l2 * (sqrt(3)-(sqrt(3)-1)*0.9));

This is nicer and faster.