How to use logic between two points with only a negavite slope?
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I have a vector that starts at ~84 decreases to ~77 and then increases to ~84 again. I am only interested in the negative slope of this vector! For example, in the image below, I am only interested in the x points between ~2100 and ~9500 as that is the decreasing slope. Using my logic selects both the negative and positive slope. I am sure there are better ways to do this. Any help would be appreciated.
wndwSize = 30;
h = ones(1,wndwSize)/wndwSize;
G = filter(h, 1,file.data.X.signals.values>78.1) & filter(h, 1,file.data.X.signals.values<82.9);
2 Comments
Jan
on 8 Aug 2017
What is shown in the diagram? Where do the values 78.1 and 82.9 come from? What does "interested in the negative slope of this vector" exactly mean? What do you need as output?
Accepted Answer
Jan
on 8 Aug 2017
"Negative slope" sounds like:
index = (gradient(file.data.X.signals.values) < 0);
Or do you mean:
v = filter(h, 1,file.data.X.signals.values);
index = (v > 78.1) & (v < 82.9);
I'm not sure about the meaning of the question.
5 Comments
Image Analyst
on 9 Aug 2017
Noise is not signal. So how does filtering out noise -- that is, removing noise to get the true signal -- make the data less precise??? The noise made the data less precise (not the filtering), so by not filtering and keeping the noise, that's what will make it less precise. I've never heard anyone say that keeping noise mixed in with their signal made it more precise than the signal alone.
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