Deleting a Cell and shifting cells left

I need to remove the n-th data (in a 1xn vector) and shift over the rest of the contents to the left by one. How would I do this?
Assume we had a cell array
a = {'1' '2' '3' '4' '5' '6' '7' '8' '9'}.
We want to delete the third entry and move over all of the data.
a{3}={}
So then
a={'1' '2' '' '4' '5' '6' '7' '8' '9'}.
Move data 1 column to the left to get rid of empty space
a={'1' '2' '4' '5' '6' '7' '8' '9'}.

 Accepted Answer

a = {'1' '2' '3' '4' '5' '6' '7' '8' '9'}
a(3)=[]

3 Comments

Much easier than I thought, perfect.
It's worth noting that a(3)=[] deletes the entry, but a{3}=[] sets the entry to contain an empty array.
Thanks for this note.

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