How to create dynamic array with flexible index?

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I am working with an RGB image and I am new to matlab.I have generated a probability matrix 1*40. Now I want to create a dynamic array with flexible index because I don't know how many values will satisfy the condition(I want to change 'P' to 1*80). for example P={0.4,0.5,0.7,0.2,0.1,0.9,0.5,0.4..........(40 values)}.If value ==0.5 I want to store the index value in an array. A(1)={2},A(2)={7}.....
Thanks in advance.

Accepted Answer

KSSV
KSSV on 5 May 2017
A = rand(1,40) ;
%%values of A less then 0.5
P = A(A<0.5) ;
%%indices of A less then 0.5
idx = find(A<0.5) ;
You need not to worry about the dimension of array which you want obeying certain condition.
  6 Comments
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Ad on 5 May 2017
Edited: Ad on 5 May 2017
@KSSV,STEPHEN COBELDICK and ADAM.
Thank you so much guys for your kind support.
Walter Roberson
Walter Roberson on 7 May 2017
Out of all of those values, 0.5 is the only one that you can hope to be able to find by using equality testing.

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