To find a vector subset of a matrix in sequence?

I have a vector A = [1 2 3] And another matrix B = [2 3 4 1; 1 2 3 4; 2 4 1 3; 2 3 1 4]

I want to know which row of vector A is subset of Matrix B (in same sequence of A, i.e. 1 2 3

The answer is 2nd row of B matrix

Answer 1

[Thibaut Jacqmin]

Here is a solution in one line :

A = [1 2 3];
B = [2 3 4 1; 1 2 3 4; 2 4 1 3; 2 3 1 4];

% Reshape B in a 1D array (all rows in a line)
C = reshape(B', [1, numel(B)]);

% Then use strfind to find a pattern in a string pattern within a string 
linear_index = strfind(C, A);

% Compute the row number of the pattern knowing the initial number of columns 
row_number = ceil(linear_index/size(B, 2));

% Or do it in a single line :
row_number = ceil(strfind(reshape(B', [1, numel(B)]), A)/size(B, 2));

[Jan]

A good idea.

The current version fails, if the searched vector appears over the margins:

B = [2 3 4 1; 2 3 1 4]

But you can filter all occurrences, which do not start between 1 and size(B,2)-length(A).

[Vishal Sharma]

please suggest code for this case