How can I make these separate for loops into a nested for loop together?

clc, clear
A = [1:11; 2:12; 3:13; 4:14; 5:15; 6:16; 7:17 ]
[M N] = size(A);
%
for i = 1:M
    Ax = [A(i, N - 5 + 1:N)  A(i, 1:N - 5)];
    Ax(1,(1:5)) = 0;
    k(i,:) = Ax;
end
%  
for j = 1:N 
    Ay = [k(1+2:M,j); 
    k(1:2,j)];
    Ay(end-1:end) = 0;
    k(:,j) = Ay;
end

This is the output: A is the starting matrix, and k is after everything is shifted over 5 and up 2. But I can't figure out how to do it as a nested for loop together.

A =

       1     2     3     4     5     6     7     8     9    10    11
       2     3     4     5     6     7     8     9    10    11    12
       3     4     5     6     7     8     9    10    11    12    13
       4     5     6     7     8     9    10    11    12    13    14
       5     6     7     8     9    10    11    12    13    14    15
       6     7     8     9    10    11    12    13    14    15    16
       7     8     9    10    11    12    13    14    15    16    17

k =

       0     0     0     0     0     3     4     5     6     7     8
       0     0     0     0     0     4     5     6     7     8     9
       0     0     0     0     0     5     6     7     8     9    10
       0     0     0     0     0     6     7     8     9    10    11
       0     0     0     0     0     7     8     9    10    11    12
       0     0     0     0     0     0     0     0     0     0     0
       0     0     0     0     0     0     0     0     0     0     0

Answer 1

[Sally Al Khamees]

Try this:

[r,c]=size(A);
k = zeros(r,c);
for i=1:(r-2)
for j = 6:c
k(i,j) = A(i+2,j-5);
end
end
k

Answer 2

[Roger Stafford]

You don’t need for-loops at all.

k = zeros(size(A));
k(1:5,6:11) = A(3:7,1:6);