Too many output arguments.Why i am getting this issue

function [T,Y] = taylor(f,a,b,ya,m)

syms t y

dfs(1) = symfun(f, [t y]); 

for k=1:3

      dfs(k+1) = diff(dfs(k),t)+f*diff(dfs(k),y);  

end

df = matlabFunction(symfun(dfs,[t y]));             

h = (b - a)/m;                                     
T = zeros(1,m+1);
Y = zeros(1,m+1);
T(1) = a;
Y(1) = ya;
for j=1:m
  tj = T(j);
  yj = Y(j);
  D = df(tj,yj);                                   
  Y(j+1) = yj + h*(D(1)+h*(D(2)/2+h*(D(3)/6+h*D(4)/24)));
  T(j+1) = a + h*j;
end
end

and i m solving f=y-t^2+1

[Image Analyst]

Why didn't you include the error message? You included only a small, virtually useless part of it. Please include ALL THE RED TEXT, after you read this if course. Also show the code you use to call your taylor() function.

Answer 1

[Tamir Suliman]

I m not sure exactly but check this code I think you might some thing you initalize to sum the variables then store it again to add it next time

function [T,Y] = taylor(f,a,b,ya,m)

syms t y
dfs(1) = symfun(f, [t y]); 
for k=1:3
      dfs(k+1) = diff(dfs(k),t)+f*diff(dfs(k),y)
end
df = matlabFunction(symfun(dfs,[t y]));             
h = (b - a)/m;                                     
T = zeros(1,m+1);
Y = zeros(1,m+1);
T(1) = a;
Y(1) = ya;
tj=0;yj=0;
for j=1:m

    D = df(tj,yj);                                   
    Y(j+1) = yj + h*(D(1)+h*(D(2)/2+h*(D(3)/6+h*D(4)/24)));
    T(j+1) = a + h*j;
    tj = T(j);
    yj = Y(j);
  end
  Tj=tj
  Yj=yj

Answer 2

[Image Analyst]

My guess is you called it expecting 3 output arguments, like this:

[T, Y, thirdArg] = taylor(f,a,b,ya,m);

but your code only returns T and Y, not thirdArg.