find the non zero minimum and return the index

I have a matrix

x = [12 10 0 6]

I need to find the non zero minimum and return the index of this non zero minimum, I have wrote

[A,I]=min(x(x>0))

It return that

A=6; I=3;

How can I get

A=6; I=4

? Thank you.

Answer 1

[Star Strider]

If you want to temporarily change ‘x’, this works:

x = [12 10 0 6];
x(x == 0 ) = NaN;
[A,I] = min(x)

A =
     6

I =
     4

You can then change the NaN back to a zero if you want to:

x(isnan(x)) = 0

x =
    12    10     0     6

Answer 2

[Image Analyst]

Try this:

% Setup
rows = 4; % Whatever you want.
columns = 4; % Whatever you want.
sigma1 = .5
m = sigma1*randn(rows, columns)

% Now begin:
% Set negative to inf
m(m<=0) = inf
minValue = min(m(:))  % Find min.
[rowOfMin, colOfMin] = find(m == minValue)  % Find row and col of min.

Answer 3

[Swarooph]

One answer could be, set anything 0 or less to NaN and directly use the min function.

x = [12 10 0 6]
x1 = x;         %Copy x into x1 if you don't want to lose x1
x1(x<=0) = NaN  %Set anything <= 0 to NaN
[A,I]=min(x1)   %Find min value and index

Now A = 6 and I = 4.