What is the logic behind fzero and fsolve which make fsolve's speed faster than fzero?

51 views (last 30 days)
What is the logic behind fzero and fsolve which make fsolve's speed faster than fzero? Suppose that there is a polynomial equation, it can be solved by root function in shortest time, following by fsolve and fzero. Why is it so?

Accepted Answer

Massimo Zanetti
Massimo Zanetti on 12 Oct 2016
Edited: Massimo Zanetti on 12 Oct 2016
The functions fsolve and fzero are not meant to solve the same problem. Specifically:
  1. fzero: It finds the root of a function (of one variable) in an interval [a,b]. It REQUIRES that f(a)*f(b)<0. fzeros uses a combination of bisection, secant, and inverse quadratic interpolation methods. Not every polynomial can be rooted by fzero: for instance x^2 doesn't work, because it has no sign change.
  2. fsolve: solves a SYSTEM of non-linear equations F(x) where x is multivariate. It use three different methods 'trust-region-dogleg' (default), 'trust-region', and 'levenberg-marquardt', depending on user needs.
  1 Comment
Dariusz Skibicki
Dariusz Skibicki on 23 Mar 2021
Thank you very much. The only sensible and simple answer. The only thing missing is the fact that fsolve is a Newtonian method.

Sign in to comment.

More Answers (0)

Categories

Find more on Optimization Toolbox in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!