I want to do element comparison between two matrices

I want to do element comparison between two matrices and if the second element is less than or equal to the previous one it should return that element as result of that matrix...for example 1 st matrix A=[1 2 3 4 5 6]; second Matrix B=[0.1 1 1.5 4.5 4 2.5 2 4]; every element of B has to be checked with A which is in ascending order and when the element of is < or = element of A that should return that value or else should go to check for next element. As a result it shall produce Result=[1 1 2 5 4 3 2 4]. I tried writing with for loop I get error dimension of two input matrix must match which is not in my case. Please help me out. TIA!

[Hems]

A=[1 2 3 4 5 6];
B=[0.1  1 1.5 4.5 4 2.5 2 4];
for i=1:max(size(B))
 for j=1:max(size(A)-1)
      if B(1,i)<=A(1,j)
         R(1,i)=A(1,j);
         break
      else
         R(1,i)=A(1,j+1);
      end
 end
end

It works !!! but is there way to make it very fast I have more than a million elements to compare.

Answer 1

[Azzi Abdelmalek]

A=[1 2 3 4 5 6];
B=[0.1  1  1.5  4.5  4  2.5  2  4]
BB=permute(B,[1 3 2])
C=bsxfun(@ge ,A,BB)
for k=1:numel(B)
  out(k)=A(find(C(:,:,k),1))
end