Does NaN used in confusion matrix affects results?

I have used confusion matrix and for making two matrices of equal dimensions I had used NaN but is it wise to use that? for example: A= [2 3 7 ]; B= [3 4 NaN]; C= A+B; C= 5 7 NaN I am getting where result should have been [5 7 7] according to me.Can anyone help? Thanx in advance.

[TastyPastry]

Why not just set the NaN to 0 before calculation? I'm assuming you need the NaN for something before adding the matrices.

[Ekta Sharma]

Sir actually 0 is one the value in my matrix as I am using chain code,in that we have directions from 0 to 7.

[Ekta Sharma]

Is there anything else we can do for making two matrices equal in length?

Answer 1

[Chad Greene]

Here's one way:

C = nansum([A; B])
C =
   5     7     7

[Ekta Sharma]

Sir may I know if I will keep using NaN in one of the matrices for making two matrices of equal dimensions.Will confusion matrix results such as true positive,false positive,true negative,false negatives values will get affected or not?

[Chad Greene]

Using NaN as a place filler is often the best way to do it. The reason 1+NaN=NaN is because Matlab doesn't what the answer is if you add a number to something that is not a number. But the nansum function and its sisters (nanmean, nanmedian, etc) are available to simply ignore NaNs the way you want.