I need to extract a row that coincides with a number in the first column.

Based on a number in column a, need to fill the rest of the row with the coinciding information.

[the cyclist]

Hi Jeff. This is not twitter. Please feel free to use more than 140 characters to describe what you are trying to do.

I'll often take a stab at what a user is going for, even if it is a bit unclear, but there is too much guesswork here. Please give a more complete explanation. An example or two of input/output is generally helpful, too.

[Image Analyst]

Actually there is not even a question here. Just an announcement. If you decide to ask a question, please read this first.

[Jeff]

Sorry guys, though I can usually figure this stuff out, I am not up on all the proper language to use. I am a simpleton with a skill above what it should be, I will try this and get back with you.

Answer 1

[Roger Stafford]

I agree with Cyclist’s comment as to the lack of clarity in your request, but I will take a very wild guess as to what you are asking. You have an array in which the values in the first column can be regarded as row indices, and that means they must be positive integers not exceeding the number of rows. You wish to replace columns (other than the first column?) by the elements that are currently in the row corresponding to that first column value if it is regarded as a row index.

Let A be your array.

A = A(A(:,1),:);

Or perhaps if you don’t want the first column values to change, you mean this:

A(:,2:end) = A(A(:,1),2:end);