Plotting a graph
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Sorry, this is a very simple question I'm sure but I just can't work it out. I'm trying to plot the error of my function that ascertains e^x for a value of x. However, when I try and plot the vectors containing the relevant information I get a load of errors.
My M-file:
function T = findexp(x,n)
%findexp, function to evaluate e^x
e=zeros(1,n);
T(1)=1;
e(1)=abs(T(1)-exp(x))/x;
for i = 2:n+1
T(i) = T(i-1)+x^(i-1)/(factorial(i-1));
e(i) = abs((T(i)-exp(x))/(x));
if i == n+1
fprintf(1,'T(%d) = %1.15e\n',x,T(i));
end
end
p=1:1:n+1;
y=e(p);
plot(p,y)
However, what I get is the output:
EDU>> findexp(1,25) T(1) = 2.718281828459046e+000 ??? Input argument "n" is undefined.
Error in ==> error at 4 e(i) = abs((findexp(x,n)-exp(x))/x);
Error in ==> clo at 20 error(nargchk(1, 3, nargin));
Error in ==> cla at 29 clo(ax, extra{:});
Error in ==> newplot>ObserveAxesNextPlot at 134 cla(ax, 'reset',hsave);
Error in ==> newplot at 83 ax = ObserveAxesNextPlot(ax, hsave);
Error in ==> findexp at 17 plot(e,p)
What am I doing wrong? Thanks for your help in advance
2 Comments
the cyclist
on 19 Jan 2012
It would be really helpful if you spent some time formatting your question better, using the Code button better.
Harry
on 19 Jan 2012
Accepted Answer
More Answers (1)
the cyclist
on 19 Jan 2012
I put the following lines of code into a file called "findexp.m"
function T = findexp(x,n)
%findexp, function to evaluate e^x
e=zeros(1,n);
T(1)=1;
e(1)=abs(T(1)-exp(x))/x;
for i = 2:n+1
T(i) = T(i-1)+x^(i-1)/(factorial(i-1));
e(i) = abs((T(i)-exp(x))/(x));
if i == n+1
fprintf(1,'T(%d) = %1.15e\n',x,T(i));
end
end
p=1:1:n+1;
y=e(p);
plot(p,y)
and then called them like this:
>> findexp(1,25)
That worked fine for me. It seems to me that the problem is not in your function findexp(), but rather in how you call it. It looks from your error message that you have not defined the second input argument, n, when you call findexp().
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