Convert floating point to binary

Hiii...
I want to ask how to convert floating point to binary in MATLAB
Thank you

 Accepted Answer

e.g.:
a = 1234.57849; % your float point number
n = 16; % number bits for integer part of your number
m = 20; % number bits for fraction part of your number
% binary number
d2b = [ fix(rem(fix(a)*pow2(-(n-1):0),2)), fix(rem( rem(a,1)*pow2(1:m),2))]; %
% the inverse transformation
b2d = d2b*pow2([n-1:-1:0 -(1:m)].');
EDIT [16:32(UTC+4) 08.01.2012]
a = 1234.57849; % your float point number
n = 16; % number bits for integer part of your number
m = 25; % number bits for fraction part of your number
% binary number
d2b = fix(rem(a*pow2(-(n-1):m),2));
% the inverse transformation
b2d = d2b*pow2(n-1:-1:-m).';

7 Comments

Been a while since I saw a 36 bit word ;-)
(Yes, I have used 36 bit computers.)
Much thanks (4 years later), this worked perfectly in my implementation of a genetic algorithm function.
for implementing GA, I used randint function to generate initial population as
d2b=randint(1,m+n);
then by the following code, decimal floating number is obtained:
b2d = d2b*pow2(n-1:-1:-m)';
DEC system 10
This code works perfectly for positive number. I run with negative number, the binary sequence contains bit 0, 1 and -1. bit -1 is not right. How can I fix this problem?
As discussed below, for negative values, you need to be specific about which representation you want to use for the binary fraction.
Thanks.

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More Answers (5)

Oliver P
Oliver P on 10 Aug 2016
Thank you for the cute and elegant solution! Unfortunately it's only working for positive floats. Negative floats will produce the same result as positive floats, but with negative bits. Which, of course, is not valid. And it's not the proper representation of negative values anyway.

5 Comments

The proper representation of negative values? As decreed by which King?
I'm not aware of a king here, but an association called IEEE. :-) The IEEE 754 format defines, for example, the leading bit convention. Matlab converts -22.9 properly to binary32 when you use:
dec2bin(typecast(single(-22.9), 'uint32'))
It's also possible to convert to binary64 in a similar way. But not to custom formats. Please do check this webpage for more info on this topic: IEEE 754 Converter
IEEE 754 defines one way to represent single precision numbers as binary, but it is far from being the only valid way.
When people ask about converting negative floating point to binary, the context is most typically the need to transmit quantized signals, which is almost always a fixed-point context, not a floating-point context. IEEE 754 does not deal with fixed point.
Yes, I agree. As far as I'm aware Matlab uses IEEE-754 for all floating-point (single, double and custom) and for unsigned fixed-point calculations. Only for signed fixed-point it's using two's-complement representation.
Walter Roberson
Walter Roberson on 12 Aug 2016
Edited: Walter Roberson on 10 Feb 2017
The "Fixed Point Toolbox" can handle floating point numbers, but are only IEEE 754 if you request very specific formats.
I do not recall that the internal format for floating point number in the Symbolic Toolbox is documented.
The Fixed Point Toolbox offers Separated Sign. I would need to recheck to see if it offers One's Complement.

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Muammar
Muammar on 8 Jan 2012
Thank you for all answers...
Aneesh paulsagin
Aneesh paulsagin on 16 Mar 2018
Edited: Walter Roberson on 3 Dec 2020
convert complex number to binary number
A = [-0.0040383664156692-0.00294191598222591i, ...
1.00279327279556+0.00768012699728154i, ...
-0.00226521017869135+0.00526418383309796i, ...
0.999498954084202-0.007158248828685i, ...
-0.00549315262581557+0.00808461388120792i, ...
0.998352426774419+0.00927983415466687i, ...
0.00736345881927219+0.00540426830690426i, ...
0.989408434745709-0.0144762821959683i, ...
0.00827899268722473+0.0122398877118786i, ...
0.999298739008971-0.0129949269950415i, ...
-5.47057549608037e-07-0.0130605748664198i, ...
1.01414402334238+0.0131228156923076i, ...
0.000678728159952879-0.00434397278237206i, ...
0.985341332736134+0.0239798712601118i, ...
0.0109818351271128-0.00658607972360998i, ...
1.01709879921672-0.00394256645505557i, ...
0.000335417716939878-0.00461609765687651i, ...
0.996785178287252-3.51718069407279e-05i, ...
-0.0137042758344959+0.00734580139566216i, ...
1.01389851161064+0.00526816880638668i, ...
-0.0143246406043654-0.0173541476823603i, ...
0.984838248467196-0.00274924075252472i, ...
-0.00383017735389232-0.00877400220581385i, ...
0.996013541706753+0.0113592028562242i, ...
-0.00607963966107746-0.00701052911751136i, ...
1.00401827238935-0.0163653626342944i]

4 Comments

A_binary = reshape(dec2bin(typecast(reshape([real(A(:).'); imag(A(:).')], 1, []),'uint64'),64).',1, []);
Ian Ono
Ian Ono on 18 Oct 2021
Edited: Ian Ono on 18 Oct 2021
Walter Robinson, If I use your line to create A_binary and then fwrite it to file. How would I fread it back?
format long g
A = [
1.01709879921672-0.00394256645505557i, ...
0.996013541706753+0.0113592028562242i, ...
-0.00607963966107746-0.00701052911751136i, ...
]
A =
1.01709879921672 - 0.00394256645505557i 0.996013541706753 + 0.0113592028562242i -0.00607963966107746 - 0.00701052911751136i
A_binary_out = reshape(dec2bin(typecast(reshape([real(A(:).'); imag(A(:).')], 1, []),'uint8'),8).',1, []);
tn = tempname(); %temporary file name
fid = fopen(tn, 'w');
fwrite(fid, A_binary_out, 'char');
fclose(fid);
fid = fopen(tn, 'r');
A_binary_in = char(fread(fid, [1 inf], 'uint8'));
fclose(fid);
pairs = typecast(uint8(bin2dec(reshape(A_binary_in, 8, []).')),'double');
A_reconstructed = pairs(1:2:end) + 1i .* pairs(2:2:end)
A_reconstructed =
1.01709879921672 - 0.00394256645505557i 0.996013541706753 + 0.0113592028562242i -0.00607963966107746 - 0.00701052911751136i
If your original A did not happen to be a column vector, then you will need a step to reshape it to the original size.
Great!
Much thanks

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on 7 Jan 2012

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on 19 Oct 2021

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