removing elements of a cell array

say we have a cell array

dictionary= 'abbreviately' 'abbreviation' 'abbreviator' 'abbreviatory' 'abbreviature' 'abby' 'abcoulomb' 'abdal'

I have written a code which returns x = 0 0 0 0 1 0 0

word='saddest'
newguess='e'
 x=newguess==word

How do I delete the words from dictionary that are not equivalent for my x value and newguess letter 'e'. So x has a true value on the 5th position (after the 4 false values), which would mean I would like to delete all the words from dictionary if their 5th position letter does not equal 'e'. Thank you

Answer 1

[Walter Roberson]

newdictionary = C( cellfun(@(C) length(C) >= 5 & C(5)==newguess, dictionary, 'Uniform', 0) );

[James Connor]

Thanks a lot for that but also, is there a way to write it in a general sense for example if x= 0 0 1 0 1 or x= 0 1 1 0 0 0

[Walter Roberson]

newdictionary = C( cellfun(@(C) length(C) == length(x) & all(C(x)==newguess), dictionary, 'Uniform', 0) );

[James Connor]

I'm so sorry I didn't define my dictionary correctly it should be

dictionary={'abbreviately';'abbreviation';'abbreviator';'abbreviatory';'abbreviature';'abby';'abcoulomb';'abdal'}

I apologise for the mistake.

[Walter Roberson]

The code I gave assumed a cell array of strings, so it should be fine with that definition of your dictionary.

[James Connor]

Oh, I don't know if it's me doing something wrong but I keep getting this.

Index exceeds matrix dimensions.

Error in @(C)length(C)==length(x)&all(C(x)==newguess)