how can i blur an image by removing high frequencies of it's DFT

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Hello everyone, I'm trying to blur an image by removing the high frequencies from the DFT of that image. after reading the image i used the fft command, now i have the frequencies but can't figure out how to remove the high ones
any suggestion??

Accepted Answer

David Young
David Young on 1 Jan 2012
There's a demo that does this here. Other such demos are available also if you look for them.
  2 Comments
hanan Sh
hanan Sh on 2 Jan 2012
thanks David your demo was helpful, i have one question though,
those lines ....
sigmaf = 10;
mask(1:N/2+1) = exp(-(f/(2*sigmaf)).^2);
mask(N:-1:N/2+2) = mask(2:N/2);
are they supposed to calculate the Gaussian mask???
David Young
David Young on 2 Jan 2012
Hi. Yes, that's what they do. The second line actually computes the Gaussian, and the third line reflects it to make the correct symmetry for a the DFT of a real signal.

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More Answers (2)

Walter Roberson
Walter Roberson on 1 Jan 2012
zero them in the dft.
  2 Comments
hanan Sh
hanan Sh on 1 Jan 2012
i tried this. the result was black image
imdft= fft2(im);
for i=1:s(1)
for j=1:s(2)
for k=1:s(3)
if (imdft (i ,j ,k)> 0)
imdft (i ,j ,k)== 0;
end
end
end
end
imdft = uint8(ifft2(imdft));
figure, imshow(imdft);

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Dr. Seis
Dr. Seis on 1 Jan 2012
I modified an example I posted earlier. It generates a random 2D image and then applies a simple low-pass filter (i.e., sets high-frequencies beyond some cut-off to 0):
Nx = 32; % Number of samples collected along x dimension
Ny = 64; % Number of samples collected along y dimension
dx = .1; % x increment (i.e., Spacing between each column)
dy = .1; % y increment (i.e., Spacing between each row)
x = 0 : dx : (Nx-1)*dx;
y = 0 : dy : (Ny-1)*dy;
data_spacedomain = randn(Ny,Nx); % random 2D matrix
Nyq_kx = 1/(2*dx); % Nyquist of data in x dimension
Nyq_ky = 1/(2*dy); % Nyquist of data in y dimension
dkx = 1/(Nx*dx); % x Wavenumber increment
dky = 1/(Ny*dy); % y Wavenumber increment
kx = -Nyq_kx : dkx : Nyq_kx-dkx; % x wavenumber
ky = -Nyq_ky : dky : Nyq_ky-dky; % y wavenumber
data_wavenumberdomain = fftshift(fft2(data_spacedomain)); % transform data
data_wavenumberdomain_filtered = data_wavenumberdomain; % copy
% Set high-frequency components with hypot(kx,ky) > 2 to 0
for i1 = 1:Nx
for j1 = 1:Ny
if hypot(kx(i1),ky(j1)) > 2
data_wavenumberdomain_filtered(j1,i1) = 0;
end
end
end
data_spacedomain_filtered = ifft2(ifftshift(data_wavenumberdomain_filtered));
figure;
subplot(3,1,1);
imagesc(kx,ky,abs(data_wavenumberdomain_filtered));
colorbar; v = caxis;
title(sprintf('Wavenumber Domain\n\nFiltered'));
xlabel('kx'); ylabel('ky');
subplot(3,1,2);
imagesc(kx,ky,abs(data_wavenumberdomain));
colorbar; caxis(v);
title('Unfiltered');
xlabel('kx'); ylabel('ky');
subplot(3,1,3);
imagesc(kx,ky,abs(data_wavenumberdomain_filtered-data_wavenumberdomain));
colorbar; caxis(v);
title('Difference');
xlabel('kx'); ylabel('ky');
figure;
subplot(3,1,1);
imagesc(x,y,data_spacedomain_filtered);
colorbar; v = caxis;
title(sprintf('Space Domain\n\nFiltered'));
xlabel('x'); ylabel('y');
subplot(3,1,2);
imagesc(x,y,data_spacedomain);
colorbar; caxis(v);
title('Unfiltered');
xlabel('x'); ylabel('y');
subplot(3,1,3);
imagesc(x,y,data_spacedomain_filtered-data_spacedomain);
colorbar; caxis(v);
title('Difference');
xlabel('x'); ylabel('y');
  1 Comment
chris crowley
chris crowley on 6 May 2020
This code works, but is pretty slow. That for loop and be completely eliminated. Replace the for loop with:
[KX,KY] = meshgrid(ky,kx);
data_wavenumberdomain_filtered(hypot(KX,KY) > 2) = 0;
Instead of looping over each index and checking the if condition, this utilizes MATLABs vectorized functionality. This runs in fractions of a second for the images I have been trying it on as apposed to a few minutes it took the above code.

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