Why isn't three divided by two 1.5?

>> x=int16(3) % set x equal to the integer 3
x =
      3
>> y=int16(2) % set y equal to the integer 2 
y =
      2
>> x/y        % divide x by y
ans =
      2

Answer 1

[Joseph Cheng]

because it's rounding due to your setting x and y as integers and not double or single precision.

Answer 2

[Walter Roberson]

Division like that on integer data types is defined as being equivalent to converting the data to double, doing the operation, and then converting back to the integer data type. The conversion of double to integer data type is defined as one that rounds. 1.5 rounds to 2 so the result is int16(2)