Cutting a certain pattern from an array

Hello everyone!

I have a simple question regarding deleting certain pattern from array. For example I have a random array

A=[1 2 3 4 5 6 0 0 0 0 1 2 3 4 5 6 7 8 9 10 0 0 0 0 ...]

I want to delete all fragments, built of four zeroes. So cut away all B=[0 0 0 0] from a 1d array.

How can I implement it?

Answer 1

[C.J. Harris]

A = [1 2 3 4 5 6 0 0 0 0 1 2 3 4 5 6 7 8 9 10 0 0 0 0];
B = [0 0 0 0];

C = A(setxor(cell2mat(arrayfun(@(x)(x:x+length(B)-1),strfind(A,B), 'UniformOutput', false)), 1:length(A)));

[Stephen23]

See my answer for a much simpler and 100x faster solution.

[beatlewalrus]

Thank you, but it turned out to be not applicable in my case. I had to be more precise: i'm using MathScript node in LabView. So for example C=setxor(A,B) works ok in MatLab but doesn't work in LabVIEW

Answer 2

[Stephen23]

>> A = [1,2,3,4,5,6,0,0,0,0,1,2,3,4,5,6,7,8,9,10,0,0,0,0];
>> B = [0,0,0,0];
>> +strrep(char(A),char(B),'')
ans =
    1    2    3    4    5    6    1    2    3    4    5    6    7    8    9   10

[Walter Roberson]

Hee, cute.

Works fine for non-negative integers up to 65535 but not in general.

[Stephen23]

True. It is also more than 100x faster than the accepted solution :)