How to assign numbers to random cells.

let n=5 m=zeros(n,n) m=rand(n,n)<0.1

and suppose the result of the above code is

m = [0 0 0 0 0; 0 0 1 0 0; 0 0 0 0 1; 0 0 0 1 0; 0 0 0 0 0]

consider the ones as the nucleation site. Now I want to assign different numbers in exact positions (in the random position of ones) as grain numbers i.e assign two values in the same cell. How to proceed.

Answer 1

[Guillaume]

Unless you change your matrix into a cell array, you can't assign two numbers to the same position, so I'm unclear what you're asking.

To assign numbers to only the non-zeros elements of m:

m(logical(m)) = rand(1, sum(m(:)))

[Vijay Reddy]

yes, the above matrix is a cell array. I want to assign different numbers to the nucleation cells(the 'ones' cell). For example: for the cell(2,3), I want to assign a number 5. For cell(4,4), I want to assign a number 10 and so on.

[Guillaume]

m is not a cell array. Matrices and cell arrays are two very different things. A matrix can only hold a single number in a cell, a cell array can have anything (including a matrix) in a single cell.

As per my answer, to assign numbers to the non-zeros elements of m:

m(logical(m)) = [5 10 ....] %there must be as many numbers to assign as there are 1 in m

What is not clear is how you decide which numbers to assign and more importantly how many in total.

[Vijay Reddy]

Thanks for your answer sir and sorry for duplicate questions. I am new to matlab coding and cellular automata and trying to learn.