Please help me to run this simple relation

I want to draw relation between T ( y-axis) and x ( x-axis) with change parameter B1.

Constant:

B2=0.01;B4=0.1;

vector

Parameter

B1=0.1:0.1:0.5

Answer 1

[Star Strider]

Probably the easiest way to do this is with a surf plot. Here, I combined it with a contour plot as well, using the surfc function.

Try something like this --

B2 = 0.01;
B4 = 0.1;
B1=0.1:0.1:0.5;
x = 0:0.01:1;
[xm,B1m] = ndgrid(x,B1);
T = (B1m-B2)./(3*B4) .* (1 + exp(xm));


figure
surfc(xm, B1m, T)
colormap(turbo)
colorbar
xlabel('x')
ylabel('B1')
zlabel('T')

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[T K]

I want to draw in 2 Dimension X-axis is X Y-axis is T Parameter is B1

[Star Strider]

I missed the fact that the first term was negated earlier. Corrected here.

Here you go ---

B2 = 0.01;
B4 = 0.1;
B1=0.1:0.1:0.5;
x = 0:0.01:1;
[xm,B1m] = ndgrid(x,B1);
T = (B1m-B2)./(3*B4) .* (exp(xm) - 1);

figure
plot(x, T)
grid
xlabel('x')
ylabel('T')
title('$T(x,B1) = \frac{(B1-B2)}{3B4}(e^x-1)$', Interpreter='LaTeX')
legend(compose('B1 = %.1f', B1), Location='best')

figure
surfc(xm, B1m, T)
colormap(turbo)
colorbar
xlabel('x')
ylabel('B1')
zlabel('T')
title('$T(x,B1) = \frac{(B1-B2)}{3B4}(e^x-1)$', Interpreter='LaTeX')

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[T K]

Oh,thanks alot professor Star. Finally, what is the importance of [xm,B1m] = ndgrid(x,B1) in this code ??

[Star Strider]

My pleasure!

That assignment creates matrices of the same sizes for 'x' and 'B1', creating 'xm' (x matrix) and 'B1m' (B1 matrix). The matrices are important because they make the calculations easier, eliminating explicit loops that would otherwise be required.

The 'T' calculation

T = (B1m-B2)./(3*B4) .* (exp(xm) - 1);

then uses them to produce its own matrix, with dimensions matching the original matrices. That makes the plotting easier.

The 'dot operators force array (element-wise) division (./) and multiplication (.*) rather than matrix division and multiplication.

.

[Star Strider]

My pleasure!

If my Answer helped you solve your problem, please Accept it!

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