Is there any expert who knows how the SNR result in the RF Budget Analyzer is calculated? Why is it inconsistent with the value I calculated?

3 views (last 30 days)
The way I calculated is:SNR=0-lg(KTB)=0-10lg(1.38*10^-23*290*100*10^6)=123.9772
There is a difference of 30 dB from the simulation result. Which part is wrong?

Accepted Answer

David Goodmanson
David Goodmanson on 15 Apr 2025
Edited: David Goodmanson on 15 Apr 2025
Hi ZW,
It's good to work out things independently as you are doing. The available power is 0 dBm, i.e. 1 milliwatt = -30 dB watts. So now you have
-30 -10*log10(1.38*10^-23*290*100*10^6)
which basically matches the result.
(Using more decimal places for the Boltzmann constant, k = 1.38065e-23, matches the result to all four decimal places).
  2 Comments
志刚
志刚 on 16 Apr 2025
It was really an enlightenment to me. Moreover, you carefully pointed out the issue of the accuracy of the value of the Boltzmann constant. Thank you DG so much!
志刚
志刚 on 16 Apr 2025
Edited: 志刚 on 16 Apr 2025
Do you know the reasons for the following two questions? As shown in the figure,
First, why the SNR remains unchanged after cascading?
Second, the OIP3 value after cascading is also different from the result I calculated.
The calculation methods I used for the cascaded SNR and the cascaded OIP3 are as follows.

Sign in to comment.

More Answers (0)

Categories

Find more on RF Blockset Models for Transceivers in Help Center and File Exchange

Products


Release

R2023a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!