Deconvolution of two different Gaussians

Hi all
I'm convolving two different Gaussians: straggling and espread. But when I deconvolve the resultant I see either straggling or "nonsense". Is it possible to deconvolve the resultant in such a way that I see espread? My code is attached.
Sorry, bit of a noob question.
Regards
Tim

 Accepted Answer

If you know a priori that all the signals are Gaussians, then deconvolution would not be the best way to recover espread. You know that the mean and variance of Gaussian signals add under convolution, so just fit a Gaussian (e.g. with this Download) to the output y and subtract its mean and variance from the known mean and variance of 'straggling'.
x1 = linspace(0, 20, 512);
dt=(x1(2)-x1(1));
straggling = GaussianPDF(x1, 7.7, 0.1);
figure; hold on;
plot(x1, straggling);
espread = GaussianPDF(x1, 7.7, 1);
% espread = espread/max(espread);
plot(x1, espread);
y = conv(straggling, espread)*dt;
x2 = (0:numel(y)-1)*dt;
plot(x2, y);
grid on;
legend('Straggling', 'E-Spread', 'Convolution');
p=gaussfitn(x2',y',[],{0,[],[]},{0,[],[]} );
espreadRec=GaussianPDF(x1,p{3}-7.7, sqrt(p{4}-0.1^2));
figure;
plot(x1,espread,'o',x1,espreadRec,'-');
legend Original Recovered
grid on;

1 Comment

Thanks Matt.
This was the clue I was looking for:
"If you know a priori that all the signals are Gaussians, then deconvolution would not be the best way to recover espread. You know that the mean and variance of Gaussian signals add under convolution, so just fit a Gaussian (e.g. with this Download) to the output y and subtract its mean and variance from the known mean and variance of 'straggling'."
Regards
Tim

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More Answers (1)

Catalytic
Catalytic on 16 Jan 2025
Edited: Catalytic on 16 Jan 2025
Is it possible to deconvolve the resultant in such a way that I see espread?
Since you deconvolve y by espread, of course you will get straggling. Presumably you meant to deconvolve by straggling -
a=deconv(y,straggling);

1 Comment

Hi Catalytic,
I tried that and got "nonsense". See attched.
Regards
Tim

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Asked:

Tim
on 14 Jan 2025

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Tim
on 20 Jan 2025

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