How to represent del Z in the following expession in MATLAB this Z is Z-transform ?

Is my lines of code correct for representation of del Z ???? which is

syms z 
Z = [1 z^-1 z^-2 z^-3 z^-4 z^-5 z^-6 z^-7 z^-8 z^-9 ].';
t = iztrans(Z);

or

function Z = Z_vector(z, N)
% Z_vector generates the vector Z(z) = [1, z^(-1), ..., z^(-N+1)]
% Input:
% z - the variable in the z-domain
% N - the number of elements in the vector

Z = z .^ (0:-1:-(N-1));
end

Please any modification or suggestions for del Z????

[Walter Roberson]

is described as based delay but you do not appear to be using 1- anywhere in your implementations.

Answer 1

[Arnav]

Hi @Rohitashya,

According to the paper, is the based delay vector, where z is substituted by in .

You can refer to the below code to obtain by symbolic substitution:

syms z 
function Z = Z_vector(z, N)
    Z = (z .^ (0:-1:-(N-1))).';
end
Z = Z_vector(z, 10);
del_Z = subs(Z, z, 1 / (1-z^-1))

You can refer to the following documentation link for more information about subs function:

https://www.mathworks.com/help/symbolic/sym.subs.html

Hope that helps.

Arnav

[Rohitashya]

Thanks