How can I write a 'for' loop that sums up all elements of a vector?

For instance, I have vector a = 1 2 3 4 5, or simply a=[1:5]. How can I write a 'for' loop that sums up all the elements while showing intermediate results? I want the last result to be 15, as in, 1+2+3+4+5. So far I've only managed to sum up elements like this: 1+2 = 3, 2+3 = 5 and so on. What I want is a 'for' loop that factors in the previous summation and sums it up with the next.

The code I've written so far is:

a= [1:5]
for i=1:5
    c=sum(a(i)+a(i+1))
    
    disp(c)
end

[VBBV]

@Seif you could also simply sum up all the elements in vector as below

a= 1:5

a = 1x5

1 2 3 4 5

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

for i=1:5
    c=a(1:i);    
    disp(['The sum is ',num2str(sum(c))])
end

The sum is 1
The sum is 3
The sum is 6
The sum is 10
The sum is 15

Answer 1

[VBBV]

@Seif do you mean like this ?

a= [1:5]

a = 1x5

1 2 3 4 5

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

for i=1:3
    c(i)=sum(a(i)+a(i+1))
    disp(sum(c))
end

c = 3

     3

c = 1x2

3 5

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

     8

c = 1x3

3 5 7

<mw-icon class=""></mw-icon>

<mw-icon class=""></mw-icon>

    15

[Seif]

That works! Thank you so much

Answer 2

[Voss]

a = 1:5;

total = 0;
for ii = 1:numel(a)
    total = total+a(ii)
end

total = 1

total = 3

total = 6

total = 10

total = 15

[Seif]

Thank you so much!

[Voss]

You're welcome! Any questions, let me know.