What Does the Symbolic Math Toolbox Mean by 0 < s When s is Complex?
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syms s
syms t real
f = int(exp(-s*t),t,-inf,0)
What does that first condition mean insofar as s is complex?
Accepted Answer
John D'Errico
on 25 Feb 2024
Edited: John D'Errico
on 25 Feb 2024
Just test it yourself. :) Admittedly, it may not have been obvious to perform this test. But we can use it to learn how MATLAB sees that comparison.
s = sym([0, 1, -1, i, -i, 1+i, 1-i, -1+i, -1-i])
s > 0
As you can see, a comparison with an inequality applies to the real part of a complex number. I do see that one of those cases in your question showed real(s)<0 as a comparison, but that would still be equivalent as far as MATLAB is concerned to s<0.
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John D'Errico
on 25 Feb 2024
Sometimes the symbolic TB does mysterious things. :)
It is confusing that real(s)<0 and s<0 are in fact the same thing as far as the STB is concerned, yet we see both of those in different paths in the same result in your example. I assume they were generated by different pieces of code, possibly involving different people in the coding.
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