# Seeking Help: Deleting Redundancy in a Structure Array

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Wei Wen on 24 Jan 2024
Commented: Bruno Luong on 24 Jan 2024
Hello,
I hope this message finds you well. I have a question regarding comparing elements in a structure array in MATLAB. Below is the code snippet I am working with, and I'm looking for guidance on identifying and removing redundancy
clear
clc
a(1).pos=[1,7,1];
a(2).pos=[1,7,1];
a(3).pos=[6,5,5];
a(4).pos=[1,4,3];
a(5).pos=[2,2,2];
In this example, I want to find and delete redundant elements within the structure array. Specifically, if I know that a(1).pos and a(2).pos have the same elements, I want to retain only one instance.
I am seeking assistance on how to code this efficiently. Any insights or code snippets would be greatly appreciated. Thank you in advance for your help!
Bruno Luong on 24 Jan 2024
Can we assume
a(i).pos
are 1 x 3 numercal array or they can be something else more generic?
Wei Wen on 24 Jan 2024
Edited: Wei Wen on 24 Jan 2024
hi, it is in numerical array.
Here is a sample of the actual value from the main code. I would like to compare the value from the pop.Position. If there is redundancy, i would like to eliminate it. Are there any ways to do that?
There is no redundancy in the figure below.

Bruno Luong on 24 Jan 2024
a(1).pos=[1,7,1];
a(2).pos=[1,7,1];
a(3).pos=[6,5,5];
a(4).pos=[1,4,3];
a(5).pos=[2,2,2];
P = cat(1, a.pos);
[~, I] = unique(P, 'rows');
a = a(sort(I));
a.pos
ans = 1×3
1 7 1
ans = 1×3
6 5 5
ans = 1×3
1 4 3
ans = 1×3
2 2 2
Wei Wen on 24 Jan 2024
Thank you !
Bruno Luong on 24 Jan 2024