Splitting numbers of vector in multiple parts

I have a vector which can vary in length, e. g. V' = [2022024 2023074 2022044 2023014 2023054]. Now my problem is that I need to split each number into specific parts:

2022024 -> 2022 024

2023074 -> 2023 074

...

Does anyone know how to do this in a loop?

Thanks in advance

Answer 1

[Bruno Luong]

If string output is desired

V = [2022024 2023074 2022044 2023014 2023054]

V = 1×5

2022024 2023074 2022044 2023014 2023054

c = mat2cell(char(arrayfun(@num2str,V,'unif',0)),ones(length(V),1),[4 3])

c = 5×2 cell array
    {'2022'}    {'024'}
    {'2023'}    {'074'}
    {'2022'}    {'044'}
    {'2023'}    {'014'}
    {'2023'}    {'054'}

string(c)

ans = 5×2 string array
    "2022"    "024"
    "2023"    "074"
    "2022"    "044"
    "2023"    "014"
    "2023"    "054"

Answer 2

[VBBV]

If you want to split array of numbers, but using a loop , here's one way

V = string([2022024 2023074 2022044 2023014 2023054]);
for k = 1:length(V)
    Num = char(V(k));    
    V_S(k,:) = [str2double(Num(1:4)) str2double(Num(5:7))];
end
V_S

V_S = 5×2

2022 24 2023 74 2022 44 2023 14 2023 54

Answer 3

[Bruno Luong]

If numerical value output is desired

V = [2022024 2023074 2022044 2023014 2023054]

V = 1×5

2022024 2023074 2022044 2023014 2023054

[floor(V/1000); mod(V,1000)]'

ans = 5×2

2022 24 2023 74 2022 44 2023 14 2023 54

Answer 4

[Sachin Hegde]

V= [2022024 2023074 2022044 2023014 2023054];
V = num2str(V);
tkn = regexp(V,'(\d+)(\d{3})','tokens');
V_split = str2double(vertcat(tkn{:}))

V_split = 5×2

2022 24 2023 74 2022 44 2023 14 2023 54

Answer 5

[Bruno Luong]

V = [2022024 2023074 2022044 2023014 2023054]

V = 1×5

2022024 2023074 2022044 2023014 2023054

s = string(V)';
s = [extractBefore(s,5) extractAfter(s,4)]

s = 5×2 string array
    "2022"    "024"
    "2023"    "074"
    "2022"    "044"
    "2023"    "014"
    "2023"    "054"