rounding elements in matrix if > or < to 0.75

example:

3.32==> .032 is < 0.75 ===> 3

0.78===>0.78 is >0.75==> 1

[Dyuman Joshi]

What should be the result when the decimal part is equal to 0.75?

Answer 1

[Cris LaPierre]

Currently, round uses 0.5 as the threshold. The quickest solution would be to modify your data by subtracting 0.25 to artificially move the threshold. Now, 0.75 become 0.5 and is still rounded up. 1.74 becomes 1.49, and is rounded down. In both cases, you end up with the value you want.

x = [3.32;0.78];
round(x-0.25)

ans = 2×1

3 1

[aldo]

" is still rounded up. 1.74 becomes 1.54"

do you mean "is still rounded up. 1.74 becomes (1.74-.25) 1,49"

thanks

[aldo]

fixed the code you wrote But I wrote wrong I want to put a decimal input and then the code runs: Ex: .75.. .82 ... .25 and if <x I round down otherwise up

[aldo]

do you think this code is correct?

function ris=Test_round(k)
x = [3.32;0.78;1.25;0.20];
 ris=round(x-(k-0.5));
end

matrix K

input:dec

x=0.75

x=.25

x=.91

[Cris LaPierre]

You can determine if it works just by testing it. Do you get the expected results?

[aldo]

ah ok...I'll have to do more appropriate numerical tests I'm bad at math :(

Answer 2

[Swapnil Tatiya]

Hi @aldo,

you could use this as another way to round your numbers according to what you desire by doing the following

x=[0.33 0.45 1.56 1.77];
x=floor(x+0.25)

x = 1×4

0 0 1 2

Hope this helps!