Is there a way to find the impulse response of the given system without using a loop?
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Is it possible to modify this code so that it would work without using any loop for the given system.
%y[n] = 1/3(x[n]-x[n-3])
y = zeros(1,21);
for i = 1:1:21
if i <= 3
y(i) = x(i)*(1/3);
else
y(i) = (x(i)-x(i-3))*(1/3);
end
end
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Answers (2)
Ram Sreekar
on 26 Jun 2023
Edited: Ram Sreekar
on 26 Jun 2023
Hi Akash knrs,
It is possible to calculate y without using a loop. You can refer to the example code given below.
% Consider,
x = [1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21];
y = zeros(1,21);
y(1:3) = x(1:3) * (1/3);
y(4:end) = (x(4:end) - x(1:end-3)) * (1/3);
Hope this helps you resolve your query.
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Mahesh Chilla
on 26 Jun 2023
Hi Akash!
Assuming that the array "x" is the unit impulse. To solve this, you can create an array of "x" which is shifted by 3 units to the right.
The following code will solve this
n = 1:21 ; %defining an interval
x = (n==0) ; % unit impulse
x3 = (n==3) ; % unit impulse shifted by 3 units to the right
y = (x-x3)/3 ;
To learn more about the functions used in the code, refer the MATLAB's documentation.
- https://www.mathworks.com/help/signal/gs/impulse-step-and-ramp-functions.html
Hope this helps,
Thank you!!
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