How should i get start with this?

The Pythagorean theorem states that a^2 + b^2 = c^2 • Write a MATLAB program in a script file that finds all the combinations of triples a, b, and c that are positive integers all smaller or equal to 50 that satisfy the Pythagorean theorem. Display the results in a three-column table in which every row corresponds to one triple. The first three rows of the table are:

   3 4 5
   5 12 13
   6 8 10

[James Tursa]

Repeated Question:

"The Pythagorean theorem states that a^2 + b^2 = c^2 • Write a MATLAB program in a script file that finds all the combinations of triples a, b, and c that are positive integers all smaller or equal to 50 that satisfy the Pythagorean theorem. Display the results in a three-column table in which every row corresponds to one triple. The first three rows of the table are:

   3 4 5
   5 12 13
   6 8 10 
"

Why are you posting this here? You already had a Question for this with Answers:

http://www.mathworks.com/matlabcentral/answers/195511-what-is-the-matlab-program-for-this

[Alex Degaga]

Thank you Joep

Answer 1

[Joep]

You can start by writing down the Pythagorean therm in matlab. The second is start a loop from 1 to 50. You could use a for loop for that.

n=1;
for a_ = 1:50
    for b_ = 1:50
        c_=sqrt(a_^2+b_^2);
        if c_==round(c_)
            if c_<=50
                a(n)=a_;
                b(n)=b_;
                c(n)=c_;
                n=n+1;
            end
        end
        clear c_
    end
end

Pyth=[a',b',c'];

disp(Pyth)

With this code you have still some double solutions. I let it to you to solve this bug. A solution could be found to let b>a and c>b but I didn't test it, so I could be wrong.

Update: I found by the way this for answer (without the bug):

       3     4     5
       5    12    13
       6     8    10
       7    24    25
       8    15    17
       9    12    15
       9    40    41
      10    24    26
      12    16    20
      12    35    37
      14    48    50
      15    20    25
      15    36    39
      16    30    34
      18    24    30
      20    21    29
      21    28    35
      24    32    40
      27    36    45
      30    40    50

[Alex Degaga]

Thank you, I had the FOLLOWING, but what you did make sense a lot!

if length(a)==1
 if length(b)==1 
   if length(c)==1  
    if a==abs(a)
     if b==abs(b)  
    if c==abs(c)
        for a=1:1:50
            b=1:1:50
             c=sqrt(a^2+b^2)
             if a<=50&&b<=50&&c<=50
             fprintf(' %i %i %i\n', a,b,c)
             elseif a>50&&b>50&&c>50
                 disp('error')
             elseif length(a)~=1,length(b)~=1, length(c)~=1

[Joep]

if a<=50&&b<=50&&c<=50

is this necessary? is

if c<=50

not enough? because a en b already are from 1 to 50.