Get the "File version" of an exe file
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How can I get the "File version" or the "Product version" of an exe file?
i can see it if:
- i'm right click on the exe file.
- click on "Properties".
- click on TAB "Details".
- under the "Description" title are listed the parameters "File version" and "Product version".
I want to read these parameters using a Matlab command.

I saw a way to get the "Owner" of the file using the commands in the link below, but I couldn't figure out how to read the "File version".
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Accepted Answer
Jan
on 28 Dec 2022
Edited: Jan
on 28 Dec 2022
Create a VBS script:
' File: FileProductVer.vbs
Set FSO=CreateObject("Scripting.FileSystemObject")
If Wscript.Arguments.Count > 0 then
sFullFileName = Wscript.Arguments(0)
If FSO.FileExists(sFullFileName) Then
Set objFolder = CreateObject("Shell.Application").Namespace(FSO.GetParentFolderName(sFullFileName))
Set objFolderItem = objFolder.ParseName(FSO.GetFileName(sFullFileName))
WScript.Echo "FileVersion : " & objFolderItem.ExtendedProperty("Fileversion")
WScript.Echo "ProductVersion: " & objFolderItem.ExtendedProperty("productversion")
Else
WScript.Echo "Error: missing file"
End If
Else
WScript.Echo "Error: missing input"
End If
Then call it from Matlab:
file = fullfile(matlabroot, 'bin', 'matlab.exe');
[status, result] = system(sprintf('cscript -nologo FileProductVer.vbs "%s"', file))
Output:
result =
'FileVersion : 1.0.0.1
ProductVersion: 9.5.0.878302
'
Parse this using strsplit and strtrim.
More Answers (1)
Wolfie
on 27 Aug 2025
Edited: Wolfie
on 27 Aug 2025
You can use .NET functionality directly. Here is the Microsoft documentation for the System.Diagnostics.FileVersionInfo function:
MATLAB code:
file = fullfile(matlabroot, 'bin', 'matlab.exe');
v = char( System.Diagnostics.FileVersionInfo.GetVersionInfo( file ).FileVersion );
Output:
v =
'24.2.0.2651190'
If you don't use the .FileVersion attribute then you'll get a structure with various fields including numeric major/minor versions.
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