What does this command (x = [(n-n0) >= 0];) do in the following code?

funtion[x,n]=stepseq(n0,n1,n2) n=[n1:n2]; x=[(n-n0)>=0];

Answer 1

[Anusha B]

Assuming n0 is a scalar and n is a vector of numbers, the statement x=[(n-n0)>=0;) will create a logical vector 'x' that will contain values of '1' and '0's based on the result of the operation (n-n0)>=0;

For example, if n0=3 and n=[1 2 3 4 5]

x=[(n-n0)>=0] will cause the vector 'x' to have the following values

x= [ 0 0 1 1 1]

Hope this helps.

[Troy]

Thank you

Answer 2

[Anusha B]

Assuming n0 is a scalar and n is a vector, the statement x=[(n-n0)>=0]; will create a logical vector 'x' that will contain values '1's or '0's based on the result of the operation (n-n0)>=0. If the condition is true for a vector element, the value returned is 1. Otherwise 0 is returned.

For example:

n0=3; n=[1 2 3 4 5]; x=[(n-n0)>=0]; % This will cause the x to have the values [0 0 1 1 1]

Hope this helps.