Add 3 to the values of x that are even

 Accepted Answer

Hi,
x(find(mod(x,2) == 0)) = x(find(mod(x,2) == 0)) + 3
or
ind = find(mod(x,2) == 0);
x(ind) = x(ind) + 3;

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Asked:

on 11 Oct 2011

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