How do I do unsigned comparsion between two vectors having 1s and 0s?

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x = '10000001000000000000000000000000'
y = '00000000000001010110001111000000'
Let's say x is the binary representation of a 32-bit unsigned number. y is also same.
I want to have unsigned comparison between both of them. That means x(1) and y(1) are the MSB and the comparsion should start from there till we reach LSB.
Thanks.

Accepted Answer

Chunru
Chunru on 29 Mar 2022
x = '10000001000000000000000000000000'
x = '10000001000000000000000000000000'
y = '00000000000001010110001111000000'
y = '00000000000001010110001111000000'
% Convert the binary to decimal
xd = bin2dec(x)
xd = 2.1643e+09
yd = bin2dec(y)
yd = 353216
% compare the decimal number
xd > yd
ans = logical
1
  2 Comments
Nadatimuj
Nadatimuj on 29 Mar 2022
Thanks. This works well for the 32-bit. Will it work for 64-bit as well?
Chunru
Chunru on 29 Mar 2022
It works forup to 53 binary bits (?).
If you have more bits to compare, you can use symbolic computation:
x = '0b100000010000000000000000000000001000000000000000000000000011';
y = '0b000000000000010101100011110000001000000000000000000000000011';
xs = sym(x)
xs = 
580964352065011715
ys = sym(y)
ys = 
94815832244227
isAlways(xs > ys)
ans = logical
1

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