how to separate a matrix into 2 vectors

hello guys, I have a problem with separating a matrix into two vectors, if the last column is 0 or 1.

I explain myself better, I have this matrix but as we can see in the last column I have 1 or 0 right? what I want to do is separate it into two groups for example.

matrix file attached.

matrix

60 13.9713945172825 20 1

59 14.3718712753277 43 1

52 21.1752085816448 20 1

48 12.7771156138259 35 0

48 20.7771156138259 35 0

47 15.1775923718712 28 1

44 18.3790226460073 57 1

41 21.5804529201432 8 1

15 21.9928486293206 29 1

12 21.1942789034565 31 1

Result

vectorof1= [60 13.9713945172825 20 1

59 14.3718712753277 43 1

52 21.1752085816448 20 1

47 15.1775923718712 28 1

44 18.3790226460073 57 1

41 21.5804529201432 8 1

15 21.9928486293206 29 1

12 21.1942789034565 31 1];

vectorof0 = [48 12.7771156138259 35 0

48 20.7771156138259 35 0];

thank you very much in advance.

Answer 1

[Dave B]

You can do this pretty easily with some indexing. Here's an example with some random data:

m = [rand(10,2) randi(2,10,1)-1]

m = 10×3

0.6389 0.4429 1.0000 0.0720 0.4878 0 0.8781 0.6126 0 0.8703 0.5697 0 0.4551 0.6683 1.0000 0.8022 0.4067 0 0.2758 0.1283 0 0.5673 0.0117 1.0000 0.1495 0.2832 0 0.0861 0.4779 0

m0 = m(m(:,3)==0,:) % read the right hand side as: from m, take the rows where the third column of m is 0, take all columns

m0 = 7×3

0.0720 0.4878 0 0.8781 0.6126 0 0.8703 0.5697 0 0.8022 0.4067 0 0.2758 0.1283 0 0.1495 0.2832 0 0.0861 0.4779 0

m1 = m(m(:,3)==1,:) % read the right hand side as: from m, take the rows where the third column of m is 1, take all columns

m1 = 3×3

0.6389 0.4429 1.0000 0.4551 0.6683 1.0000 0.5673 0.0117 1.0000

To understand how this works, you can look at what you're feeding in:

ind = m(:,3)==1

ind = 10×1 logical array
   1
   0
   0
   0
   1
   0
   0
   1
   0
   0

(importantly it's displayed as 1 and 0, but note it's a "logical array" it's really true, false, false, false, true, ...)