Reshape by rows instead of columns

I have a 1260 by 1 column vector (myVector) that I want to reshape to a 35*36 matrix. However, I can't figure out how to reshape it the particular way that I want:

reshape(myVector,35,36) takes each successive chunk of 35 elements from myVector and makes them the 36 columns of the new matrix. But I want to take each successive chunk of 36 elements from myVector and make each chunk the 35 rows of the new matrix. How do I do this?

Answer 1

[Max Alger-Meyer]

If I understand you correctly, all you need to do is transpose the reshaped result:

vector = 1:16

vector = 1×16

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

array1 = reshape(vector,4,4)

array1 = 4×4

1 5 9 13 2 6 10 14 3 7 11 15 4 8 12 16

transpose(array1)

ans = 4×4

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

[Adam Fitchett]

This solution only works if the desired matrix is square

However, I figured out a solution for non-square matrices: reshape first with the desired dimensions swapped and then transpose

So to get the desired 35*36 matrix, first do reshape(myVector,36,35), and then ans = ans'

[James Tursa]

Note that you can transpose the result of reshape directly, e.g.,

myMatrix = reshape(myVector,36,35)';

If elements could be complex then use the .' operator instead of the ' operator:

myMatrix = reshape(myVector,36,35).';

[Amr Aboughazala]

I don't see this is a right answer if you have a matrix of different size.

x = [0,1,2,3,4,5]

it should be like if row wise x = reshape(x,3,2)

x =

0 1

2 3

4 5

if it is column wise

x =

0 3

1 4

2 5

The second is the answer when you use reshape(x,3,2)

taking the transpose won't give the first answer

[Bruno Luong]

@Amr Aboughazala "taking the transpose won't give the first answer"

because you take transpose on a wrong reshape.

The correct one is

x = [0,1,2,3,4,5];
reshape(x,[2,3])' % size is [2,3] not [3,2]

ans = 3×2

0 1 2 3 4 5

It does fine.

[Amr Aboughazala]

I just noticed that, thank you so much for your reply :)