Make first and last element of array 0

N = 12*0.5;
TAU_max = 15;

for i = 1:N

TAU(i,:) = i*(TAU_max/N);

end 

I have a little loop here that creates a column vector with my dummy variables. But how I do make it so the (1,1) and (1:N) elements are 0 while still preserving my original values?

[Stephen23]

You don't need a loop:

N = 12*0.5;
TAU_max = 15;
TAU = (1:N)*(TAU_max/N)

TAU = 1×6

2.5000 5.0000 7.5000 10.0000 12.5000 15.0000

Answer 1

[Voss]

Pre-allocate TAU as a vector of zeros, then just set elements 2 through N-1:

N = 12*0.5;
TAU_max = 15;
TAU = zeros(N,1); % pre-allocate
for i = 2:N-1
    TAU(i,:) = i*TAU_max/N;
end
disp(TAU);

         0
    5.0000
    7.5000
   10.0000
   12.5000
         0

Alternatively, set all elements and afterward set elements 1 and N to zero:

N = 12*0.5;
TAU_max = 15;
TAU = zeros(N,1);
for i = 1:N
    TAU(i,:) = i*TAU_max/N;
end
TAU([1 N],:) = 0;
disp(TAU);

         0
    5.0000
    7.5000
   10.0000
   12.5000
         0

Answer 2

[Arif Hoq]

try this:

N = 12*0.5;
TAU_max = 15;
for i = 1:N
TAU(i,:) = i*(TAU_max/N);
TAU([1 N],:)=0;
end 
disp(TAU)

         0
    5.0000
    7.5000
   10.0000
   12.5000
         0