how to extract a value with a specific character out of an character array

a great example to describe this would be for emails. Say we have an input of:
emails = 'someone, random@gmail, other'
how would one know to select the one with the @gmail and then add the .com to the end after?
If there are multiple emails in the array, only display the first one.

 Accepted Answer

I'm not sure which extra emails should be rejected. I'm going to assume that all other emails get rejected
emails = {'someone, random@gmail, backupaccount@yahoo, other';
'someone else, random2@hotmail, other'};
mailhost = regexp(emails,'@[^,]*','match');
mailhost1all = [mailhost{1}{1} '.com']
mailhost1all = '@gmail.com'
If instead there might be more than one email per entry in the emails array, and you only want the first email per entry in the array:
mailhost1each = cell(numel(emails),1);
for acct = 1:numel(emails)
mailhost1each{acct} = [mailhost{acct}{1} '.com'];
end
mailhost1each
mailhost1each = 2×1 cell array
{'@gmail.com' } {'@hotmail.com'}

3 Comments

it would need to include the username of the email as well. It can work for both @gmail and @yahoo, but it it's @earthlink it would need to end with .net instead of .com
mailhost1each=strrep(mailhost1each,'@earthlink.com','@earthlink.net');
Maybe something like this?
emails = {'someone, random@gmail, backupaccount@yahoo, other';
'someone else, random2@earthlink, other'};
% match the whole email address
mailaccounts = regexp(emails,'[^,\s]*?@[^,]*','match');
% these hosts should be .net
hasnettld = {'earthlink','comcast','airmail','charter'};
hasnettld = cellfun(@(x) ['@' x],hasnettld,'uniform',false);
firstmailaccounts = cell(numel(emails),1);
for acct = 1:numel(emails)
thisacct = mailaccounts{acct}{1};
if contains(thisacct,hasnettld)
firstmailaccounts{acct} = [thisacct '.net'];
else
firstmailaccounts{acct} = [thisacct '.com'];
end
end
firstmailaccounts
firstmailaccounts = 2×1 cell array
{'random@gmail.com' } {'random2@earthlink.net'}
I'm sure this can be simplified, but I'm still not really sure what you want matched.

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Products

Release

R2021a

Asked:

on 24 Feb 2022

Commented:

DGM
on 25 Feb 2022

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