How to find elements of first matrix based on second matrix?

I have two matrices A and B

A = [1 2 3 4 5 6 7 8 9 10];

B = [1 0 0 1 0 1 0 1 1 1];

How to find entries of A coresponsing to '1' in B

result = [1 4 6 8 9 10];

[Stephen23]

Note that FIND is not required, logical indexing is simpler and more efficient:

A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
C = A(B==1)

C = 1×6

1 4 6 8 9 10

Answer 1

[Arif Hoq]

use find function

A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
result=A(find(B==1))

result = 1×6

1 4 6 8 9 10

[Stephen23]

FIND is not required, logical indexing is simpler and more efficient:

A = [1 2 3 4 5 6 7 8 9 10];
B = [1 0 0 1 0 1 0 1 1 1];
C = A(B==1)

C = 1×6

1 4 6 8 9 10

[Ammy]

@Arif Hoq, @Stephen many thanks