Similar lines are much different in time for run due to MATLAB profiler.

2 views (last 30 days)
hosein bashi
hosein bashi on 13 Jan 2022
Answered: Philip Borghesani on 20 Jan 2022
The right hand side of all of below equation are numbers (in same order of magnitude) but the first line is much slower. Any idea why this is happening? The image of profile is also attached.
% Comp.Yp(j,1)=Yp;
% Comp.Yp1(j,1)=Yp1;
% Comp.Yp2(j,1)=Yp2;
% Comp.Yt(j,1)=Yt;
% Comp.Y_sh(j,1)=Y_sh;
% Comp.Y_Ex(j,1)=Y_Ex;
  3 Comments
Philip Borghesani
Philip Borghesani on 20 Jan 2022
You are calling this funciton quite a few times. Without more understanding of your code it is unlikely that a good anwer can be supplied. Some questions and things to think about:
  1. Is your object a handle or value object? If it is simple give some info about it or the code.
  2. How are you calling this function? what are the inputs and outputs?
  3. Are your members (Yp1,Yp2,...) preallocated?
Most likely the best way to improve your code is to restructure it so that the helper function can be vectorized and not called so many times.

Sign in to comment.

Answers (2)

Fangjun Jiang
Fangjun Jiang on 13 Jan 2022
It takes time to create "Comp" as a structure. Add the line below first and then profile again.
Comp=struct;
  1 Comment
hosein bashi
hosein bashi on 13 Jan 2022
Thank you. But as I explained for Rik in previous comment the Comp is an object which is input (and output) of a function. so I think it's previously an structure.

Sign in to comment.


Philip Borghesani
Philip Borghesani on 20 Jan 2022
Most likely this is happining due to memory allocation, caching and array growth. Unfortunatly this answer wont help you much.... See my comments to your question

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!