why do I suddenly get a gain value in my transfer function?
9 views (last 30 days)
Show older comments
this is my transfer function:
x=s/[(2*s^2)+(3*s)+1]
when I tried to obtained the zeros and poles value by using zpk function suddenly I got a gain value.

any advice will be much appreciated. thank you in advance
0 Comments
Accepted Answer
Jon
on 1 Dec 2021
Your original expression and the one found by zpk are the same. zpk just factored out the 2 from denominator.
2 Comments
Jon
on 1 Dec 2021
Note that 1/(2s^2 + 3s + 1) = 1/(2*(s^2 + 1.5s + 0.5), which equals, 0.5/(s^2 + 1.5s + 0.5). So you also have a gain of 0.5 in your original expession
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!